12013130011447 has 2 divisors, whose sum is σ = 12013130011448. Its totient is φ = 12013130011446.

The previous prime is 12013130011327. The next prime is 12013130011459. The reversal of 12013130011447 is 74411003131021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013130011447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013130011847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006565005723 + 6006565005724.

It is an arithmetic number, because the mean of its divisors is an integer number (6006565005724).

Almost surely, 2^{12013130011447} is an apocalyptic number.

12013130011447 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013130011447 is an equidigital number, since it uses as much as digits as its factorization.

12013130011447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 12013130011447 its reverse (74411003131021), we get a palindrome (86424133142468).

The spelling of 12013130011447 in words is "twelve trillion, thirteen billion, one hundred thirty million, eleven thousand, four hundred forty-seven".