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1201313020023 = 32929143680543
BaseRepresentation
bin10001011110110011110…
…101011111100001110111
311020211210120101102211200
4101132303311133201313
5124140242113120043
62315513043103543
7152535441121524
oct21366365374167
94224716342750
101201313020023
11423523977506
121749a5371bb3
138938b63102c
1442202a7814b
15213b00ed7d3
hex117b3d5f877

1201313020023 has 12 divisors (see below), whose sum is σ = 1737097776960. Its totient is φ = 800013257856.

The previous prime is 1201313019979. The next prime is 1201313020027. The reversal of 1201313020023 is 3200203131021.

It is not a de Polignac number, because 1201313020023 - 212 = 1201313015927 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201313019978 and 1201313020005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201313020027) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71831911 + ... + 71848632.

It is an arithmetic number, because the mean of its divisors is an integer number (144758148080).

Almost surely, 21201313020023 is an apocalyptic number.

1201313020023 is a deficient number, since it is larger than the sum of its proper divisors (535784756937).

1201313020023 is a wasteful number, since it uses less digits than its factorization.

1201313020023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143681478 (or 143681475 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 1201313020023 its reverse (3200203131021), we get a palindrome (4401516151044).

The spelling of 1201313020023 in words is "one trillion, two hundred one billion, three hundred thirteen million, twenty thousand, twenty-three".

Divisors: 1 3 9 929 2787 8361 143680543 431041629 1293124887 133479224447 400437673341 1201313020023