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120131304311 = 751715981283
BaseRepresentation
bin110111111100001100…
…0100011101101110111
3102111002011020120011002
41233320120203231313
53432012103214221
6131104302433515
711451652144544
oct1577030435567
9374064216132
10120131304311
1146a46a97a87
121b34789289b
13b43646b725
145b58965bcb
1531d179080b
hex1bf8623b77

120131304311 has 4 divisors (see below), whose sum is σ = 120147293112. Its totient is φ = 120115315512.

The previous prime is 120131304289. The next prime is 120131304323. The reversal of 120131304311 is 113403131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120131304311 - 234 = 102951435127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131334311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7983125 + ... + 7998158.

It is an arithmetic number, because the mean of its divisors is an integer number (30036823278).

Almost surely, 2120131304311 is an apocalyptic number.

120131304311 is a deficient number, since it is larger than the sum of its proper divisors (15988801).

120131304311 is an equidigital number, since it uses as much as digits as its factorization.

120131304311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15988800.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 120131304311 its reverse (113403131021), we get a palindrome (233534435332).

The spelling of 120131304311 in words is "one hundred twenty billion, one hundred thirty-one million, three hundred four thousand, three hundred eleven".

Divisors: 1 7517 15981283 120131304311