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120131313103 = 280957427579
BaseRepresentation
bin110111111100001100…
…0100101110111001111
3102111002011021000012201
41233320120211313033
53432012104004403
6131104302542331
711451652212304
oct1577030456717
9374064230181
10120131313103
1146a46aa364a
121b3478979a7
13b436472729
145b589690ab
1531d179321d
hex1bf8625dcf

120131313103 has 4 divisors (see below), whose sum is σ = 120132021640. Its totient is φ = 120130604568.

The previous prime is 120131313031. The next prime is 120131313131. The reversal of 120131313103 is 301313131021.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 120131313103 - 221 = 120129215951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131313173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67168 + ... + 494746.

It is an arithmetic number, because the mean of its divisors is an integer number (30033005410).

Almost surely, 2120131313103 is an apocalyptic number.

120131313103 is a deficient number, since it is larger than the sum of its proper divisors (708537).

120131313103 is an equidigital number, since it uses as much as digits as its factorization.

120131313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 708536.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 120131313103 its reverse (301313131021), we get a palindrome (421444444124).

The spelling of 120131313103 in words is "one hundred twenty billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred three".

Divisors: 1 280957 427579 120131313103