Search a number
-
+
1201313211202 = 21379757972841
BaseRepresentation
bin10001011110110011110…
…110001110001101000010
311020211210120202011002101
4101132303312032031002
5124140242140224302
62315513051141014
7152535442546066
oct21366366161502
94224716664071
101201313211202
11423523a98105
121749a544476a
138938b69a060
1442202ac7aa6
15213b013a287
hex117b3d8e342

1201313211202 has 16 divisors (see below), whose sum is σ = 1943017772472. Its totient is φ = 553756567680.

The previous prime is 1201313211167. The next prime is 1201313211233. The reversal of 1201313211202 is 2021123131021.

It can be written as a sum of positive squares in 4 ways, for example, as 548741674441 + 652571536761 = 740771^2 + 807819^2 .

It is a super-2 number, since 2×12013132112022 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1201313211202.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28965699 + ... + 29007142.

Almost surely, 21201313211202 is an apocalyptic number.

1201313211202 is a deficient number, since it is larger than the sum of its proper divisors (741704561270).

1201313211202 is a wasteful number, since it uses less digits than its factorization.

1201313211202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57973653.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1201313211202 its reverse (2021123131021), we get a palindrome (3222436342223).

It can be divided in two parts, 120131 and 3211202, that added together give a palindrome (3331333).

The spelling of 1201313211202 in words is "one trillion, two hundred one billion, three hundred thirteen million, two hundred eleven thousand, two hundred two".

Divisors: 1 2 13 26 797 1594 10361 20722 57972841 115945682 753646933 1507293866 46204354277 92408708554 600656605601 1201313211202