120132001323131 has 8 divisors (see below), whose sum is σ = 139544432450784. Its totient is φ = 101282249358720.

The previous prime is 120132001323073. The next prime is 120132001323137. The reversal of 120132001323131 is 131323100231021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120132001323131 is a prime.

It is a super-2 number, since 2×120132001323131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120132001323097 and 120132001323106.

It is not an unprimeable number, because it can be changed into a prime (120132001323137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 140669790350 + ... + 140669791203.

It is an arithmetic number, because the mean of its divisors is an integer number (17443054056348).

Almost surely, 2^{120132001323131} is an apocalyptic number.

120132001323131 is a deficient number, since it is larger than the sum of its proper divisors (19412431127653).

120132001323131 is an equidigital number, since it uses as much as digits as its factorization.

120132001323131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281339581621.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 120132001323131 its reverse (131323100231021), we get a palindrome (251455101554152).

The spelling of 120132001323131 in words is "one hundred twenty trillion, one hundred thirty-two billion, one million, three hundred twenty-three thousand, one hundred thirty-one".