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1201320023231 = 8531031408177
BaseRepresentation
bin10001011110110100010…
…000001101010010111111
311020211211001120020102202
4101132310100031102333
5124140300411220411
62315513453142115
7152535554500166
oct21366420152277
94224731506382
101201320023231
11423527920089
121749a778a93b
138938cc13843
144220397c3dd
15213b0a3383b
hex117b440d4bf

1201320023231 has 4 divisors (see below), whose sum is σ = 1201322284512. Its totient is φ = 1201317761952.

The previous prime is 1201320023227. The next prime is 1201320023287. The reversal of 1201320023231 is 1323200231021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201320023231 - 22 = 1201320023227 is a prime.

It is a super-2 number, since 2×12013200232312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201320023731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149015 + ... + 1557191.

It is an arithmetic number, because the mean of its divisors is an integer number (300330571128).

Almost surely, 21201320023231 is an apocalyptic number.

1201320023231 is a deficient number, since it is larger than the sum of its proper divisors (2261281).

1201320023231 is an equidigital number, since it uses as much as digits as its factorization.

1201320023231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2261280.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1201320023231 its reverse (1323200231021), we get a palindrome (2524520254252).

The spelling of 1201320023231 in words is "one trillion, two hundred one billion, three hundred twenty million, twenty-three thousand, two hundred thirty-one".

Divisors: 1 853103 1408177 1201320023231