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12013203101 = 71167168803
BaseRepresentation
bin10110011000000101…
…01110111010011101
31011000012221221121012
423030002232322131
5144100334444401
65304020345005
7603461353514
oct131402567235
934005857535
1012013203101
11510515a329
1223b3245165
131195b08303
1481d69767b
154a49cc8bb
hex2cc0aee9d

12013203101 has 4 divisors (see below), whose sum is σ = 12013443072. Its totient is φ = 12012963132.

The previous prime is 12013203047. The next prime is 12013203127. The reversal of 12013203101 is 10130231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013203101 - 218 = 12012940957 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013203151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13235 + ... + 155568.

It is an arithmetic number, because the mean of its divisors is an integer number (3003360768).

Almost surely, 212013203101 is an apocalyptic number.

It is an amenable number.

12013203101 is a deficient number, since it is larger than the sum of its proper divisors (239971).

12013203101 is an equidigital number, since it uses as much as digits as its factorization.

12013203101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 239970.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 12013203101 its reverse (10130231021), we get a palindrome (22143434122).

The spelling of 12013203101 in words is "twelve billion, thirteen million, two hundred three thousand, one hundred one".

Divisors: 1 71167 168803 12013203101