12013212021 has 4 divisors (see below), whose sum is σ = 16017616032. Its totient is φ = 8008808012.

The previous prime is 12013212019. The next prime is 12013212047. The reversal of 12013212021 is 12021231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013212021 - 2¹ = 12013212019 is a prime.

It is a super-2 number, since 2×12013212021² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013212221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002202001 + ... + 2002202006.

It is an arithmetic number, because the mean of its divisors is an integer number (4004404008).

Almost surely, 2^12013212021 is an apocalyptic number.

It is an amenable number.

12013212021 is a deficient number, since it is larger than the sum of its proper divisors (4004404011).

12013212021 is an equidigital number, since it uses as much as digits as its factorization.

12013212021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4004404010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12013212021 its reverse (12021231021), we get a palindrome (24034443042).

The spelling of 12013212021 in words is "twelve billion, thirteen million, two hundred twelve thousand, twenty-one".