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120132200109 = 340044066703
BaseRepresentation
bin110111111100001101…
…1111110011010101101
3102111002012221001221210
41233320123332122231
53432012320400414
6131104333545033
711451662565315
oct1577033763255
9374065831853
10120132200109
1146a4754a009
121b348045179
13b4366c339c
145b58b1a445
1531d18bae59
hex1bf86fe6ad

120132200109 has 4 divisors (see below), whose sum is σ = 160176266816. Its totient is φ = 80088133404.

The previous prime is 120132200107. The next prime is 120132200131. The reversal of 120132200109 is 901002231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 120132200109 - 21 = 120132200107 is a prime.

It is a super-2 number, since 2×1201322001092 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120132200107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20022033349 + ... + 20022033354.

It is an arithmetic number, because the mean of its divisors is an integer number (40044066704).

Almost surely, 2120132200109 is an apocalyptic number.

It is an amenable number.

120132200109 is a deficient number, since it is larger than the sum of its proper divisors (40044066707).

120132200109 is an equidigital number, since it uses as much as digits as its factorization.

120132200109 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40044066706.

The product of its (nonzero) digits is 216, while the sum is 21.

It can be divided in two parts, 12013 and 2200109, that added together give a palindrome (2212122).

The spelling of 120132200109 in words is "one hundred twenty billion, one hundred thirty-two million, two hundred thousand, one hundred nine".

Divisors: 1 3 40044066703 120132200109