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1201323312103 = 7628211574843
BaseRepresentation
bin10001011110110100011…
…100110000001111100111
311020211211021202022220211
4101132310130300033213
5124140302231441403
62315514051440251
7152535624445555
oct21366434601747
94224737668824
101201323312103
11423529767062
121749a88b6087
13893907c5815
1442204196bd5
15213b0e8306d
hex117b47303e7

1201323312103 has 4 divisors (see below), whose sum is σ = 1201325649768. Its totient is φ = 1201320974440.

The previous prime is 1201323312097. The next prime is 1201323312131. The reversal of 1201323312103 is 3012133231021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201323312103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201323312173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24601 + ... + 1550242.

It is an arithmetic number, because the mean of its divisors is an integer number (300331412442).

Almost surely, 21201323312103 is an apocalyptic number.

1201323312103 is a deficient number, since it is larger than the sum of its proper divisors (2337665).

1201323312103 is an equidigital number, since it uses as much as digits as its factorization.

1201323312103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2337664.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1201323312103 its reverse (3012133231021), we get a palindrome (4213456543124).

The spelling of 1201323312103 in words is "one trillion, two hundred one billion, three hundred twenty-three million, three hundred twelve thousand, one hundred three".

Divisors: 1 762821 1574843 1201323312103