Base | Representation |
---|---|
bin | 11011010100001001111101… |
… | …011110111100110011100100 |
3 | 120202100112120100211202022020 |
4 | 123110021331132330303210 |
5 | 111221222013134101000 |
6 | 1103300011345503140 |
7 | 34206163250155230 |
oct | 3324117536746344 |
9 | 522315510752266 |
10 | 120132340534500 |
11 | 3530692642a578 |
12 | 11582551941ab0 |
13 | 520557b199558 |
14 | 21946173195c0 |
15 | dd4db7be5ba0 |
hex | 6d427d7bcce4 |
120132340534500 has 192 divisors, whose sum is σ = 401275717140480. Its totient is φ = 27357495984000.
The previous prime is 120132340534457. The next prime is 120132340534501. The reversal of 120132340534500 is 5435043231021.
It is not an unprimeable number, because it can be changed into a prime (120132340534501) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 18263680 + ... + 23954679.
It is an arithmetic number, because the mean of its divisors is an integer number (2089977693440).
Almost surely, 2120132340534500 is an apocalyptic number.
120132340534500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120132340534500 is an abundant number, since it is smaller than the sum of its proper divisors (281143376605980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120132340534500 is a wasteful number, since it uses less digits than its factorization.
120132340534500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42218659 (or 42218647 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 120132340534500 its reverse (5435043231021), we get a palindrome (125567383765521).
The spelling of 120132340534500 in words is "one hundred twenty trillion, one hundred thirty-two billion, three hundred forty million, five hundred thirty-four thousand, five hundred".
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