Base | Representation |
---|---|
bin | 10110011000000101… |
… | …11000001111111101 |
3 | 1011000020000220001111 |
4 | 23030002320033331 |
5 | 144100342210331 |
6 | 5304021242021 |
7 | 603461603143 |
oct | 131402701775 |
9 | 34006026044 |
10 | 12013241341 |
11 | 5105186032 |
12 | 23b3263311 |
13 | 1195b1c83a |
14 | 81d6a7593 |
15 | 4a49d8db1 |
hex | 2cc0b83fd |
12013241341 has 4 divisors (see below), whose sum is σ = 12100929372. Its totient is φ = 11925553312.
The previous prime is 12013241327. The next prime is 12013241347. The reversal of 12013241341 is 14314231021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4643877316 + 7369364025 = 68146^2 + 85845^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013241341 - 29 = 12013240829 is a prime.
It is a super-2 number, since 2×120132413412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013241347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43843810 + ... + 43844083.
It is an arithmetic number, because the mean of its divisors is an integer number (3025232343).
Almost surely, 212013241341 is an apocalyptic number.
It is an amenable number.
12013241341 is a deficient number, since it is larger than the sum of its proper divisors (87688031).
12013241341 is an equidigital number, since it uses as much as digits as its factorization.
12013241341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87688030.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 12013241341 its reverse (14314231021), we get a palindrome (26327472362).
The spelling of 12013241341 in words is "twelve billion, thirteen million, two hundred forty-one thousand, three hundred forty-one".
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