Base | Representation |
---|---|
bin | 10110011000000101… |
… | …11000100010111011 |
3 | 1011000020000221201110 |
4 | 23030002320202323 |
5 | 144100342230210 |
6 | 5304021251403 |
7 | 603461606526 |
oct | 131402704273 |
9 | 34006027643 |
10 | 12013242555 |
11 | 5105186a36 |
12 | 23b3263b63 |
13 | 1195b20262 |
14 | 81d6a7bbd |
15 | 4a49d9420 |
hex | 2cc0b88bb |
12013242555 has 8 divisors (see below), whose sum is σ = 19221188112. Its totient is φ = 6407062688.
The previous prime is 12013242551. The next prime is 12013242557. The reversal of 12013242555 is 55524231021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12013242555 - 22 = 12013242551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12013242551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 400441404 + ... + 400441433.
It is an arithmetic number, because the mean of its divisors is an integer number (2402648514).
Almost surely, 212013242555 is an apocalyptic number.
12013242555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12013242555 is a deficient number, since it is larger than the sum of its proper divisors (7207945557).
12013242555 is an equidigital number, since it uses as much as digits as its factorization.
12013242555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 800882845.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 12013242555 its reverse (55524231021), we get a palindrome (67537473576).
The spelling of 12013242555 in words is "twelve billion, thirteen million, two hundred forty-two thousand, five hundred fifty-five".
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