12013244023 has 4 divisors (see below), whose sum is σ = 13105357128. Its totient is φ = 10921130920.

The previous prime is 12013244017. The next prime is 12013244029. The reversal of 12013244023 is 32044231021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32044231021 = 11 ⋅2913111911.

It is an interprime number because it is at equal distance from previous prime (12013244017) and next prime (12013244029).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013244023 is a prime.

It is a super-2 number, since 2×12013244023² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013243985 and 12013244003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013244029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546056536 + ... + 546056557.

It is an arithmetic number, because the mean of its divisors is an integer number (3276339282).

Almost surely, 2^12013244023 is an apocalyptic number.

12013244023 is a deficient number, since it is larger than the sum of its proper divisors (1092113105).

12013244023 is a wasteful number, since it uses less digits than its factorization.

12013244023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1092113104.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 12013244023 its reverse (32044231021), we get a palindrome (44057475044).

It can be divided in two parts, 12013 and 244023, that added together give a square (256036 = 506²).

The spelling of 12013244023 in words is "twelve billion, thirteen million, two hundred forty-four thousand, twenty-three".