Base | Representation |
---|---|
bin | 10001011110110101010… |
… | …001101110011011101010 |
3 | 11020211212020212211012221 |
4 | 101132311101232123222 |
5 | 124140314310321224 |
6 | 2315515305224254 |
7 | 152536153462261 |
oct | 21366521563352 |
9 | 4224766784187 |
10 | 1201337198314 |
11 | 423536590a70 |
12 | 1749b149208a |
13 | 89393648206 |
14 | 42205d6d5d8 |
15 | 213b22c76e4 |
hex | 117b546e6ea |
1201337198314 has 8 divisors (see below), whose sum is σ = 1965824506368. Its totient is φ = 546062362860.
The previous prime is 1201337198279. The next prime is 1201337198359. The reversal of 1201337198314 is 4138917331021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-4 number, since 4×12013371983144 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27303118122 + ... + 27303118165.
It is an arithmetic number, because the mean of its divisors is an integer number (245728063296).
Almost surely, 21201337198314 is an apocalyptic number.
1201337198314 is a deficient number, since it is larger than the sum of its proper divisors (764487308054).
1201337198314 is a wasteful number, since it uses less digits than its factorization.
1201337198314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54606236300.
The product of its (nonzero) digits is 108864, while the sum is 43.
The spelling of 1201337198314 in words is "one trillion, two hundred one billion, three hundred thirty-seven million, one hundred ninety-eight thousand, three hundred fourteen".
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