Base | Representation |
---|---|
bin | 1010111011010001011010… |
… | …1001001001101000001001 |
3 | 1120112110200201222000212012 |
4 | 2232310112221021220021 |
5 | 3033311422233204001 |
6 | 41314514211425305 |
7 | 2346640223105234 |
oct | 256642651115011 |
9 | 46473621860765 |
10 | 12013403413001 |
11 | 3911946046431 |
12 | 14203405b5235 |
13 | 691b225294b3 |
14 | 2d7647b5a41b |
15 | 15c7699ac2bb |
hex | aed16a49a09 |
12013403413001 has 8 divisors (see below), whose sum is σ = 12027674159424. Its totient is φ = 11999138664240.
The previous prime is 12013403412931. The next prime is 12013403413043. The reversal of 12013403413001 is 10031430431021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12013403413001 - 242 = 7615356901897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013403418001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2515370 + ... + 5509436.
It is an arithmetic number, because the mean of its divisors is an integer number (1503459269928).
Almost surely, 212013403413001 is an apocalyptic number.
It is an amenable number.
12013403413001 is a deficient number, since it is larger than the sum of its proper divisors (14270746423).
12013403413001 is a wasteful number, since it uses less digits than its factorization.
12013403413001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2998831.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 12013403413001 its reverse (10031430431021), we get a palindrome (22044833844022).
The spelling of 12013403413001 in words is "twelve trillion, thirteen billion, four hundred three million, four hundred thirteen thousand, one".
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