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12013403413002 = 2319105380731693
BaseRepresentation
bin1010111011010001011010…
…1001001001101000001010
31120112110200201222000212020
42232310112221021220022
53033311422233204002
641314514211425310
72346640223105235
oct256642651115012
946473621860766
1012013403413002
113911946046432
1214203405b5236
13691b225294b4
142d7647b5a41c
1515c7699ac2bc
hexaed16a49a0a

12013403413002 has 16 divisors (see below), whose sum is σ = 25291375606560. Its totient is φ = 3793706340912.

The previous prime is 12013403412931. The next prime is 12013403413043. The reversal of 12013403413002 is 20031430431021.

It is a happy number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52690365733 + ... + 52690365960.

It is an arithmetic number, because the mean of its divisors is an integer number (1580710975410).

Almost surely, 212013403413002 is an apocalyptic number.

12013403413002 is an abundant number, since it is smaller than the sum of its proper divisors (13277972193558).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013403413002 is a wasteful number, since it uses less digits than its factorization.

12013403413002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105380731717.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 12013403413002 its reverse (20031430431021), we get a palindrome (32044833844023).

The spelling of 12013403413002 in words is "twelve trillion, thirteen billion, four hundred three million, four hundred thirteen thousand, two".

Divisors: 1 2 3 6 19 38 57 114 105380731693 210761463386 316142195079 632284390158 2002233902167 4004467804334 6006701706501 12013403413002