120134145401551 has 4 divisors (see below), whose sum is σ = 120148569007600. Its totient is φ = 120119721795504.

The previous prime is 120134145401513. The next prime is 120134145401597. The reversal of 120134145401551 is 155104541431021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120134145401551 - 2¹¹ = 120134145399503 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120134145401551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120134145404551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7211790531 + ... + 7211807188.

It is an arithmetic number, because the mean of its divisors is an integer number (30037142251900).

Almost surely, 2^{120134145401551} is an apocalyptic number.

120134145401551 is a deficient number, since it is larger than the sum of its proper divisors (14423606049).

120134145401551 is an equidigital number, since it uses as much as digits as its factorization.

120134145401551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14423606048.

The product of its (nonzero) digits is 48000, while the sum is 37.

Adding to 120134145401551 its reverse (155104541431021), we get a palindrome (275238686832572).

The spelling of 120134145401551 in words is "one hundred twenty trillion, one hundred thirty-four billion, one hundred forty-five million, four hundred one thousand, five hundred fifty-one".