Base | Representation |
---|---|
bin | 11011010100001011101101… |
… | …000010000101000100000101 |
3 | 120202100201101210100210000102 |
4 | 123110023231002011010011 |
5 | 111221234331233424331 |
6 | 1103300521202053445 |
7 | 34206260523401540 |
oct | 3324135502050405 |
9 | 522321353323012 |
10 | 120134212014341 |
11 | 353076a6876028 |
12 | 1158299464a285 |
13 | 52057b8b25885 |
14 | 2194753abb857 |
15 | dd4e7716d4cb |
hex | 6d42ed085105 |
120134212014341 has 4 divisors (see below), whose sum is σ = 137296242302112. Its totient is φ = 102972181726572.
The previous prime is 120134212014331. The next prime is 120134212014361. The reversal of 120134212014341 is 143410212431021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120134212014341 is a prime.
It is a super-3 number, since 3×1201342120143413 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120134212014331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8581015143875 + ... + 8581015143888.
It is an arithmetic number, because the mean of its divisors is an integer number (34324060575528).
Almost surely, 2120134212014341 is an apocalyptic number.
It is an amenable number.
120134212014341 is a deficient number, since it is larger than the sum of its proper divisors (17162030287771).
120134212014341 is an equidigital number, since it uses as much as digits as its factorization.
120134212014341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17162030287770.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 120134212014341 its reverse (143410212431021), we get a palindrome (263544424445362).
The spelling of 120134212014341 in words is "one hundred twenty trillion, one hundred thirty-four billion, two hundred twelve million, fourteen thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •