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12013435661621 = 44926755981429
BaseRepresentation
bin1010111011010001100010…
…0100001010110100110101
31120112110202222122102122112
42232310120210022310311
53033312004012132441
641314521322540405
72346641064160442
oct256643044126465
946473688572575
1012013435661621
113911962272289
12142034b367705
13691b2910ab14
142d764c1529c9
1515c76c72c4eb
hexaed1890ad35

12013435661621 has 4 divisors (see below), whose sum is σ = 12040191643500. Its totient is φ = 11986679679744.

The previous prime is 12013435661551. The next prime is 12013435661629. The reversal of 12013435661621 is 12616653431021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6993644702500 + 5019790959121 = 2644550^2 + 2240489^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12013435661621 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013435661629) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13377990266 + ... + 13377991163.

It is an arithmetic number, because the mean of its divisors is an integer number (3010047910875).

Almost surely, 212013435661621 is an apocalyptic number.

It is an amenable number.

12013435661621 is a deficient number, since it is larger than the sum of its proper divisors (26755981879).

12013435661621 is an equidigital number, since it uses as much as digits as its factorization.

12013435661621 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26755981878.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 12013435661621 in words is "twelve trillion, thirteen billion, four hundred thirty-five million, six hundred sixty-one thousand, six hundred twenty-one".

Divisors: 1 449 26755981429 12013435661621