Base | Representation |
---|---|
bin | 11011010100010001001100… |
… | …101101001111000010010001 |
3 | 120202101021121222110201101202 |
4 | 123110101030231033002101 |
5 | 111221333422201131233 |
6 | 1103303334450040545 |
7 | 34206556655506511 |
oct | 3324211455170221 |
9 | 522337558421352 |
10 | 120140112130193 |
11 | 3530a154284431 |
12 | 11583b60579155 |
13 | 52062192bb79c |
14 | 2194b53529841 |
15 | dd51c0125be8 |
hex | 6d444cb4f091 |
120140112130193 has 4 divisors (see below), whose sum is σ = 122934068226288. Its totient is φ = 117346156034100.
The previous prime is 120140112130183. The next prime is 120140112130211. The reversal of 120140112130193 is 391031211041021.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120140112130193 - 238 = 119865234223249 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (120140112130183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1396978047983 + ... + 1396978048068.
It is an arithmetic number, because the mean of its divisors is an integer number (30733517056572).
Almost surely, 2120140112130193 is an apocalyptic number.
It is an amenable number.
120140112130193 is a deficient number, since it is larger than the sum of its proper divisors (2793956096095).
120140112130193 is an equidigital number, since it uses as much as digits as its factorization.
120140112130193 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2793956096094.
The product of its (nonzero) digits is 1296, while the sum is 29.
The spelling of 120140112130193 in words is "one hundred twenty trillion, one hundred forty billion, one hundred twelve million, one hundred thirty thousand, one hundred ninety-three".
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