12014200241021 has 4 divisors (see below), whose sum is σ = 13106400262944. Its totient is φ = 10922000219100.

The previous prime is 12014200240997. The next prime is 12014200241053.

12014200241021 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12014200241021 - 2¹⁰ = 12014200239997 is a prime.

It is a super-2 number, since 2×12014200241021² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12014200240984 and 12014200241002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12014200246021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546100010945 + ... + 546100010966.

It is an arithmetic number, because the mean of its divisors is an integer number (3276600065736).

Almost surely, 2^{12014200241021} is an apocalyptic number.

12014200241021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12014200241021 is a deficient number, since it is larger than the sum of its proper divisors (1092200021923).

12014200241021 is a wasteful number, since it uses less digits than its factorization.

12014200241021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1092200021922.

The product of its (nonzero) digits is 256, while the sum is 20.

It can be divided in two parts, 12014200 and 241021, that added together give a palindrome (12255221).

The spelling of 12014200241021 in words is "twelve trillion, fourteen billion, two hundred million, two hundred forty-one thousand, twenty-one".