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120142040320135 = 524028408064027
BaseRepresentation
bin11011010100010010111111…
…101000101100100010000111
3120202101110121100200220202001
4123110102333220230202013
5111221401344310221020
61103304254045530131
734206655521035521
oct3324227750544207
9522343540626661
10120142040320135
113530aa53734039
12115843ba273947
135206465912492
142194c97650a11
15dd528455150a
hex6d44bfa2c887

120142040320135 has 4 divisors (see below), whose sum is σ = 144170448384168. Its totient is φ = 96113632256104.

The previous prime is 120142040320117. The next prime is 120142040320193. The reversal of 120142040320135 is 531023040241021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120142040320135 - 217 = 120142040189063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12014204032009 + ... + 12014204032018.

It is an arithmetic number, because the mean of its divisors is an integer number (36042612096042).

Almost surely, 2120142040320135 is an apocalyptic number.

120142040320135 is a deficient number, since it is larger than the sum of its proper divisors (24028408064033).

120142040320135 is an equidigital number, since it uses as much as digits as its factorization.

120142040320135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24028408064032.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 120142040320135 its reverse (531023040241021), we get a palindrome (651165080561156).

The spelling of 120142040320135 in words is "one hundred twenty trillion, one hundred forty-two billion, forty million, three hundred twenty thousand, one hundred thirty-five".

Divisors: 1 5 24028408064027 120142040320135