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1201424433 = 31136406801
BaseRepresentation
bin100011110011100…
…0100100000110001
310002201200200111020
41013213010200301
54430031040213
6315114410053
741525640066
oct10747044061
93081620436
101201424433
11567199a60
12296430929
13161ba2941
14b57c0c6d
157071c923
hex479c4831

1201424433 has 8 divisors (see below), whose sum is σ = 1747526496. Its totient is φ = 728136000.

The previous prime is 1201424363. The next prime is 1201424467. The reversal of 1201424433 is 3344241021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1201424433 - 220 = 1200375857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1201424233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18203368 + ... + 18203433.

It is an arithmetic number, because the mean of its divisors is an integer number (218440812).

Almost surely, 21201424433 is an apocalyptic number.

It is an amenable number.

1201424433 is a deficient number, since it is larger than the sum of its proper divisors (546102063).

1201424433 is a wasteful number, since it uses less digits than its factorization.

1201424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36406815.

The product of its (nonzero) digits is 2304, while the sum is 24.

The square root of 1201424433 is about 34661.5699730984. The cubic root of 1201424433 is about 1063.0788712380.

Adding to 1201424433 its reverse (3344241021), we get a palindrome (4545665454).

The spelling of 1201424433 in words is "one billion, two hundred one million, four hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 3 11 33 36406801 109220403 400474811 1201424433