Base | Representation |
---|---|
bin | 1010111011010100110110… |
… | …0111001010111100101011 |
3 | 1120112120002000022001211212 |
4 | 2232311031213022330223 |
5 | 3033320314331003003 |
6 | 41315145514143335 |
7 | 2350002121652510 |
oct | 256651547127453 |
9 | 46476060261755 |
10 | 12014325641003 |
11 | 391227967aa34 |
12 | 1420559421b4b |
13 | 691c3b60643a |
14 | 2d76d4421307 |
15 | 15c7c0929dd8 |
hex | aed4d9caf2b |
12014325641003 has 8 divisors (see below), whose sum is σ = 13731782423040. Its totient is φ = 10297149995880.
The previous prime is 12014325640991. The next prime is 12014325641027. The reversal of 12014325641003 is 30014652341021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12014325641003 - 214 = 12014325624619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12014325641033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70192643 + ... + 70363596.
It is an arithmetic number, because the mean of its divisors is an integer number (1716472802880).
Almost surely, 212014325641003 is an apocalyptic number.
12014325641003 is a deficient number, since it is larger than the sum of its proper divisors (1717456782037).
12014325641003 is a wasteful number, since it uses less digits than its factorization.
12014325641003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140568457.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 12014325641003 its reverse (30014652341021), we get a palindrome (42028977982024).
The spelling of 12014325641003 in words is "twelve trillion, fourteen billion, three hundred twenty-five million, six hundred forty-one thousand, three".
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