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12014325641003 = 712211140556239
BaseRepresentation
bin1010111011010100110110…
…0111001010111100101011
31120112120002000022001211212
42232311031213022330223
53033320314331003003
641315145514143335
72350002121652510
oct256651547127453
946476060261755
1012014325641003
11391227967aa34
121420559421b4b
13691c3b60643a
142d76d4421307
1515c7c0929dd8
hexaed4d9caf2b

12014325641003 has 8 divisors (see below), whose sum is σ = 13731782423040. Its totient is φ = 10297149995880.

The previous prime is 12014325640991. The next prime is 12014325641027. The reversal of 12014325641003 is 30014652341021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12014325641003 - 214 = 12014325624619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12014325641033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70192643 + ... + 70363596.

It is an arithmetic number, because the mean of its divisors is an integer number (1716472802880).

Almost surely, 212014325641003 is an apocalyptic number.

12014325641003 is a deficient number, since it is larger than the sum of its proper divisors (1717456782037).

12014325641003 is a wasteful number, since it uses less digits than its factorization.

12014325641003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140568457.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 12014325641003 its reverse (30014652341021), we get a palindrome (42028977982024).

The spelling of 12014325641003 in words is "twelve trillion, fourteen billion, three hundred twenty-five million, six hundred forty-one thousand, three".

Divisors: 1 7 12211 85477 140556239 983893673 1716332234429 12014325641003