12014401214131 has 8 divisors (see below), whose sum is σ = 12578434177680. Its totient is φ = 11460351135072.

The previous prime is 12014401214089. The next prime is 12014401214161. The reversal of 12014401214131 is 13141210441021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12014401214131 - 2¹¹ = 12014401212083 is a prime.

It is a super-2 number, since 2×12014401214131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12014401214096 and 12014401214105.

It is not an unprimeable number, because it can be changed into a prime (12014401214161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2495718660 + ... + 2495723473.

It is an arithmetic number, because the mean of its divisors is an integer number (1572304272210).

Almost surely, 2^{12014401214131} is an apocalyptic number.

12014401214131 is a deficient number, since it is larger than the sum of its proper divisors (564032963549).

12014401214131 is an equidigital number, since it uses as much as digits as its factorization.

12014401214131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4991442245.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 12014401214131 its reverse (13141210441021), we get a palindrome (25155611655152).

The spelling of 12014401214131 in words is "twelve trillion, fourteen billion, four hundred one million, two hundred fourteen thousand, one hundred thirty-one".