1201520053 has 4 divisors (see below), whose sum is σ = 1201870080. Its totient is φ = 1201170028.

The previous prime is 1201520051. The next prime is 1201520059. The reversal of 1201520053 is 3500251021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3500251021 = 23 ⋅152184827.

It is a cyclic number.

It is not a de Polignac number, because 1201520053 - 2¹ = 1201520051 is a prime.

It is a super-2 number, since 2×1201520053² = 2887300875522245618, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201520053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201520051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169813 + ... + 176746.

It is an arithmetic number, because the mean of its divisors is an integer number (300467520).

Almost surely, 2^1201520053 is an apocalyptic number.

It is an amenable number.

1201520053 is a deficient number, since it is larger than the sum of its proper divisors (350027).

1201520053 is an equidigital number, since it uses as much as digits as its factorization.

1201520053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 350026.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 1201520053 is about 34662.9492830601. The cubic root of 1201520053 is about 1063.1070735680.

Adding to 1201520053 its reverse (3500251021), we get a palindrome (4701771074).

The spelling of 1201520053 in words is "one billion, two hundred one million, five hundred twenty thousand, fifty-three".