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12015202043 = 131310370537
BaseRepresentation
bin10110011000010100…
…10110111011111011
31011000100201111122002
423030022112323323
5144101342431133
65304131251215
7603514350365
oct131412267373
934010644562
1012015202043
1151062a5149
1223b3a49b0b
131196358110
1481da57d35
154a4c74ce8
hex2cc296efb

12015202043 has 8 divisors (see below), whose sum is σ = 12940619328. Its totient is φ = 11089952064.

The previous prime is 12015202033. The next prime is 12015202049. The reversal of 12015202043 is 34020251021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12015202043 - 218 = 12014939899 is a prime.

It is a super-2 number, since 2×120152020432 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12015202049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 135071 + ... + 205607.

It is an arithmetic number, because the mean of its divisors is an integer number (1617577416).

Almost surely, 212015202043 is an apocalyptic number.

12015202043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12015202043 is a deficient number, since it is larger than the sum of its proper divisors (925417285).

12015202043 is a wasteful number, since it uses less digits than its factorization.

12015202043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83653.

The product of its (nonzero) digits is 480, while the sum is 20.

Adding to 12015202043 its reverse (34020251021), we get a palindrome (46035453064).

The spelling of 12015202043 in words is "twelve billion, fifteen million, two hundred two thousand, forty-three".

Divisors: 1 13 13103 70537 170339 916981 924246311 12015202043