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BaseRepresentation
bin11001100101111
3122222022
43030233
5404403
6140355
753126
oct31457
918868
1013103
119932
1276bb
135c6c
144abd
153d38
hex332f

13103 has 2 divisors, whose sum is σ = 13104. Its totient is φ = 13102.

The previous prime is 13099. The next prime is 13109. The reversal of 13103 is 30131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13103 - 22 = 13099 is a prime.

It is a Chen prime.

It is a plaindrome in base 14.

It is a nialpdrome in base 11.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551 + 6552.

It is an arithmetic number, because the mean of its divisors is an integer number (6552).

213103 is an apocalyptic number.

13103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103 is an equidigital number, since it uses as much as digits as its factorization.

13103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 8.

The square root of 13103 is about 114.4683362332. The cubic root of 13103 is about 23.5752829414.

Adding to 13103 its reverse (30131), we get a palindrome (43234).

The spelling of 13103 in words is "thirteen thousand, one hundred three".