12015329983 has 4 divisors (see below), whose sum is σ = 12020464888. Its totient is φ = 12010195080.

The previous prime is 12015329951. The next prime is 12015329987. The reversal of 12015329983 is 38992351021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38992351021 = 13 ⋅2999411617.

It is a cyclic number.

It is not a de Polignac number, because 12015329983 - 2⁵ = 12015329951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12015329987) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2563941 + ... + 2568622.

It is an arithmetic number, because the mean of its divisors is an integer number (3005116222).

Almost surely, 2^12015329983 is an apocalyptic number.

12015329983 is a deficient number, since it is larger than the sum of its proper divisors (5134905).

12015329983 is an equidigital number, since it uses as much as digits as its factorization.

12015329983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5134904.

The product of its (nonzero) digits is 116640, while the sum is 43.

The spelling of 12015329983 in words is "twelve billion, fifteen million, three hundred twenty-nine thousand, nine hundred eighty-three".