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12017253000 = 2335319434903
BaseRepresentation
bin10110011000100100…
…01011101010001000
31011000111120201000110
423030102023222020
5144102404044000
65304243234320
7603540652014
oct131422135210
934014521013
1012017253000
115107476055
1223b46789a0
1311968c57bc
1482002d544
154a502c850
hex2cc48ba88

12017253000 has 256 divisors, whose sum is σ = 40393267200. Its totient is φ = 2964729600.

The previous prime is 12017252963. The next prime is 12017253091. The reversal of 12017253000 is 35271021.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2448549 + ... + 2453451.

It is an arithmetic number, because the mean of its divisors is an integer number (157786200).

Almost surely, 212017253000 is an apocalyptic number.

12017253000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12017253000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20196633600).

12017253000 is an abundant number, since it is smaller than the sum of its proper divisors (28376014200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12017253000 is a wasteful number, since it uses less digits than its factorization.

12017253000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4989 (or 4975 counting only the distinct ones).

The product of its (nonzero) digits is 420, while the sum is 21.

The spelling of 12017253000 in words is "twelve billion, seventeen million, two hundred fifty-three thousand".