Base | Representation |
---|---|
bin | 11011010101001001000100… |
… | …011100101101000011100001 |
3 | 120202121000110212002211000122 |
4 | 123111021010130231003201 |
5 | 111223324302344333441 |
6 | 1103351055353130025 |
7 | 34214112415512632 |
oct | 3325110434550341 |
9 | 522530425084018 |
10 | 120200103121121 |
11 | 35332639668881 |
12 | 115937033b9915 |
13 | 520ba89c1315a |
14 | 2197a04b15889 |
15 | dd6a31b9934b |
hex | 6d524472d0e1 |
120200103121121 has 4 divisors (see below), whose sum is σ = 120202903138500. Its totient is φ = 120197303103744.
The previous prime is 120200103121067. The next prime is 120200103121169. The reversal of 120200103121121 is 121121301002021.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 28198224040000 + 92001879081121 = 5310200^2 + 9591761^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120200103121121 is a prime.
It is a super-3 number, since 3×1202001031211213 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 120200103121121.
It is not an unprimeable number, because it can be changed into a prime (120200103126121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1399944296 + ... + 1400030153.
It is an arithmetic number, because the mean of its divisors is an integer number (30050725784625).
Almost surely, 2120200103121121 is an apocalyptic number.
It is an amenable number.
120200103121121 is a deficient number, since it is larger than the sum of its proper divisors (2800017379).
120200103121121 is an equidigital number, since it uses as much as digits as its factorization.
120200103121121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2800017378.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 120200103121121 its reverse (121121301002021), we get a palindrome (241321404123142).
The spelling of 120200103121121 in words is "one hundred twenty trillion, two hundred billion, one hundred three million, one hundred twenty-one thousand, one hundred twenty-one".
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