120202010113 has 4 divisors (see below), whose sum is σ = 120204950320. Its totient is φ = 120199069908.

The previous prime is 120202010101. The next prime is 120202010171. The reversal of 120202010113 is 311010202021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120202010113 - 2²⁵ = 120168455681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120202010093 and 120202010102.

It is not an unprimeable number, because it can be changed into a prime (120202010183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1407903 + ... + 1490836.

It is an arithmetic number, because the mean of its divisors is an integer number (30051237580).

Almost surely, 2^120202010113 is an apocalyptic number.

It is an amenable number.

120202010113 is a deficient number, since it is larger than the sum of its proper divisors (2940207).

120202010113 is an equidigital number, since it uses as much as digits as its factorization.

120202010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2940206.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 120202010113 its reverse (311010202021), we get a palindrome (431212212134).

The spelling of 120202010113 in words is "one hundred twenty billion, two hundred two million, ten thousand, one hundred thirteen".