1202023000113 has 32 divisors (see below), whose sum is σ = 1816961731200. Its totient is φ = 700720989696.

The previous prime is 1202023000081. The next prime is 1202023000127. The reversal of 1202023000113 is 3110003202021.

It is not a de Polignac number, because 1202023000113 - 2⁵ = 1202023000081 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1202023000092 and 1202023000101.

It is not an unprimeable number, because it can be changed into a prime (1202023000153) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10963381 + ... + 11072477.

It is an arithmetic number, because the mean of its divisors is an integer number (56780054100).

Almost surely, 2^{1202023000113} is an apocalyptic number.

1202023000113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1202023000113 is a deficient number, since it is larger than the sum of its proper divisors (614938731087).

1202023000113 is a wasteful number, since it uses less digits than its factorization.

1202023000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124001.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1202023000113 its reverse (3110003202021), we get a palindrome (4312026202134).

The spelling of 1202023000113 in words is "one trillion, two hundred two billion, twenty-three million, one hundred thirteen", and thus it is an aban number.