Base | Representation |
---|---|
bin | 110111111110010011… |
… | …1011011001001000101 |
3 | 102111021002212000221022 |
4 | 1233330213123021011 |
5 | 3432133242411323 |
6 | 131115320400525 |
7 | 11453503531046 |
oct | 1577447331105 |
9 | 374232760838 |
10 | 120202310213 |
11 | 46a83085847 |
12 | 1b367616145 |
13 | b4480a005b |
14 | 5b6416a8cd |
15 | 31d7b194c8 |
hex | 1bfc9db245 |
120202310213 has 4 divisors (see below), whose sum is σ = 120249804768. Its totient is φ = 120154815660.
The previous prime is 120202310171. The next prime is 120202310233. The reversal of 120202310213 is 312013202021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120202310213 - 26 = 120202310149 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120202310191 and 120202310200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120202310233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23743481 + ... + 23748542.
It is an arithmetic number, because the mean of its divisors is an integer number (30062451192).
Almost surely, 2120202310213 is an apocalyptic number.
It is an amenable number.
120202310213 is a deficient number, since it is larger than the sum of its proper divisors (47494555).
120202310213 is an equidigital number, since it uses as much as digits as its factorization.
120202310213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47494554.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 120202310213 its reverse (312013202021), we get a palindrome (432215512234).
The spelling of 120202310213 in words is "one hundred twenty billion, two hundred two million, three hundred ten thousand, two hundred thirteen".
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