12020301213122 has 4 divisors (see below), whose sum is σ = 18030451819686. Its totient is φ = 6010150606560.

The previous prime is 12020301213103. The next prime is 12020301213143. The reversal of 12020301213122 is 22131210302021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6596940539401 + 5423360673721 = 2568451^2 + 2328811^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12020301213094 and 12020301213103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3005075303279 + ... + 3005075303282.

Almost surely, 2^{12020301213122} is an apocalyptic number.

12020301213122 is a deficient number, since it is larger than the sum of its proper divisors (6010150606564).

12020301213122 is an equidigital number, since it uses as much as digits as its factorization.

12020301213122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6010150606563.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12020301213122 its reverse (22131210302021), we get a palindrome (34151511515143).

The spelling of 12020301213122 in words is "twelve trillion, twenty billion, three hundred one million, two hundred thirteen thousand, one hundred twenty-two".