120203322013031 has 4 divisors (see below), whose sum is σ = 120706264783200. Its totient is φ = 119700379242864.

The previous prime is 120203322012979. The next prime is 120203322013121. The reversal of 120203322013031 is 130310223302021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120203322013031 - 2⁶ = 120203322012967 is a prime.

It is a super-2 number, since 2×120203322013031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120203322012988 and 120203322013006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120203322013531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251471384726 + ... + 251471385203.

It is an arithmetic number, because the mean of its divisors is an integer number (30176566195800).

Almost surely, 2^{120203322013031} is an apocalyptic number.

120203322013031 is a deficient number, since it is larger than the sum of its proper divisors (502942770169).

120203322013031 is an equidigital number, since it uses as much as digits as its factorization.

120203322013031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502942770168.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120203322013031 its reverse (130310223302021), we get a palindrome (250513545315052).

The spelling of 120203322013031 in words is "one hundred twenty trillion, two hundred three billion, three hundred twenty-two million, thirteen thousand, thirty-one".