Base | Representation |
---|---|
bin | 10110011000111011… |
… | …11101101010101111 |
3 | 1011000201101121112111 |
4 | 23030131331222233 |
5 | 144104201411143 |
6 | 5304433344451 |
7 | 603606134116 |
oct | 131435755257 |
9 | 34021347474 |
10 | 12020341423 |
11 | 5109195472 |
12 | 23b5708127 |
13 | 119743747c |
14 | 8205d4c7d |
15 | 4a543c99d |
hex | 2cc77daaf |
12020341423 has 4 divisors (see below), whose sum is σ = 12030123240. Its totient is φ = 12010559608.
The previous prime is 12020341391. The next prime is 12020341447. The reversal of 12020341423 is 32414302021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12020341423 - 25 = 12020341391 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12020341394 and 12020341403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12020311423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4889065 + ... + 4891522.
It is an arithmetic number, because the mean of its divisors is an integer number (3007530810).
Almost surely, 212020341423 is an apocalyptic number.
12020341423 is a deficient number, since it is larger than the sum of its proper divisors (9781817).
12020341423 is an equidigital number, since it uses as much as digits as its factorization.
12020341423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9781816.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 12020341423 its reverse (32414302021), we get a palindrome (44434643444).
The spelling of 12020341423 in words is "twelve billion, twenty million, three hundred forty-one thousand, four hundred twenty-three".
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