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120204310034 = 260102155017
BaseRepresentation
bin110111111110010111…
…1000011011000010010
3102111021020121122011202
41233330233003120102
53432134300410114
6131115431311202
711453526530324
oct1577457033022
9374236548152
10120204310034
1146a84221296
121b36821b502
13b448620393
145b6452b614
1531d7db1cde
hex1bfcbc3612

120204310034 has 4 divisors (see below), whose sum is σ = 180306465054. Its totient is φ = 60102155016.

The previous prime is 120204310007. The next prime is 120204310063. The reversal of 120204310034 is 430013402021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430013402021 = 761430486003.

It can be written as a sum of positive squares in only one way, i.e., 113571022009 + 6633288025 = 337003^2 + 81445^2 .

It is a junction number, because it is equal to n+sod(n) for n = 120204309988 and 120204310015.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30051077507 + ... + 30051077510.

Almost surely, 2120204310034 is an apocalyptic number.

120204310034 is a deficient number, since it is larger than the sum of its proper divisors (60102155020).

120204310034 is an equidigital number, since it uses as much as digits as its factorization.

120204310034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60102155019.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 120204310034 its reverse (430013402021), we get a palindrome (550217712055).

The spelling of 120204310034 in words is "one hundred twenty billion, two hundred four million, three hundred ten thousand, thirty-four".

Divisors: 1 2 60102155017 120204310034