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12020437477 = 12163988279
BaseRepresentation
bin10110011000111100…
…10101000111100101
31011000201120111022001
423030132111013211
5144104212444402
65304435405301
7603610014136
oct131436250745
934021514261
1012020437477
115109250654
1223b5753831
13119746c0c9
1482061bc8d
154a545b187
hex2cc7951e5

12020437477 has 4 divisors (see below), whose sum is σ = 12021437920. Its totient is φ = 12019437036.

The previous prime is 12020437421. The next prime is 12020437547. The reversal of 12020437477 is 77473402021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12020437477 is a prime.

It is a super-2 number, since 2×120204374772 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12020437417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 481977 + ... + 506302.

It is an arithmetic number, because the mean of its divisors is an integer number (3005359480).

Almost surely, 212020437477 is an apocalyptic number.

It is an amenable number.

12020437477 is a deficient number, since it is larger than the sum of its proper divisors (1000443).

12020437477 is an equidigital number, since it uses as much as digits as its factorization.

12020437477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000442.

The product of its (nonzero) digits is 65856, while the sum is 37.

Adding to 12020437477 its reverse (77473402021), we get a palindrome (89493839498).

The spelling of 12020437477 in words is "twelve billion, twenty million, four hundred thirty-seven thousand, four hundred seventy-seven".

Divisors: 1 12163 988279 12020437477