Base | Representation |
---|---|
bin | 110111111110100100… |
… | …1011010011010000111 |
3 | 102111021201121201000020 |
4 | 1233331021122122013 |
5 | 3432143033020403 |
6 | 131120235350223 |
7 | 11453642340312 |
oct | 1577511323207 |
9 | 374251551006 |
10 | 120211220103 |
11 | 46a88110997 |
12 | 1b36a5b2373 |
13 | b449b9c690 |
14 | 5b65409979 |
15 | 31d87c9453 |
hex | 1bfd25a687 |
120211220103 has 16 divisors (see below), whose sum is σ = 172624324320. Its totient is φ = 73970417664.
The previous prime is 120211220033. The next prime is 120211220111. The reversal of 120211220103 is 301022112021.
It is not a de Polignac number, because 120211220103 - 221 = 120209122951 is a prime.
It is a super-2 number, since 2×1202112201032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120212220103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 423175 + ... + 647687.
It is an arithmetic number, because the mean of its divisors is an integer number (10789020270).
Almost surely, 2120211220103 is an apocalyptic number.
120211220103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120211220103 is a deficient number, since it is larger than the sum of its proper divisors (52413104217).
120211220103 is a wasteful number, since it uses less digits than its factorization.
120211220103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238258.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 120211220103 its reverse (301022112021), we get a palindrome (421233332124).
The spelling of 120211220103 in words is "one hundred twenty billion, two hundred eleven million, two hundred twenty thousand, one hundred three".
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