120213203201303 has 4 divisors (see below), whose sum is σ = 120215150697840. Its totient is φ = 120211255704768.

The previous prime is 120213203201269. The next prime is 120213203201309. The reversal of 120213203201303 is 303102302312021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120213203201303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120213203201309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 973655675 + ... + 973779132.

It is an arithmetic number, because the mean of its divisors is an integer number (30053787674460).

Almost surely, 2^{120213203201303} is an apocalyptic number.

120213203201303 is a deficient number, since it is larger than the sum of its proper divisors (1947496537).

120213203201303 is an equidigital number, since it uses as much as digits as its factorization.

120213203201303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1947496536.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120213203201303 its reverse (303102302312021), we get a palindrome (423315505513324).

The spelling of 120213203201303 in words is "one hundred twenty trillion, two hundred thirteen billion, two hundred three million, two hundred one thousand, three hundred three".