Base | Representation |
---|---|
bin | 11011010101011100100011… |
… | …001100101110110001011011 |
3 | 120202200000110121010120021102 |
4 | 123111130203030232301123 |
5 | 111224200122122402303 |
6 | 1103404435121102015 |
7 | 34215452644214240 |
oct | 3325344314566133 |
9 | 522600417116242 |
10 | 120221020122203 |
11 | 353404a2781330 |
12 | 1159778048790b |
13 | 5210a41587880 |
14 | 2198a2ab015c7 |
15 | dd735819e288 |
hex | 6d572332ec5b |
120221020122203 has 32 divisors (see below), whose sum is σ = 166981691842560. Its totient is φ = 83490845880960.
The previous prime is 120221020122131. The next prime is 120221020122211. The reversal of 120221020122203 is 302221020122021.
It is not a de Polignac number, because 120221020122203 - 28 = 120221020121947 is a prime.
It is not an unprimeable number, because it can be changed into a prime (120221020122233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2070676475 + ... + 2070734532.
It is an arithmetic number, because the mean of its divisors is an integer number (5218177870080).
Almost surely, 2120221020122203 is an apocalyptic number.
120221020122203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
120221020122203 is a deficient number, since it is larger than the sum of its proper divisors (46760671720357).
120221020122203 is a wasteful number, since it uses less digits than its factorization.
120221020122203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4141411067.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 120221020122203 its reverse (302221020122021), we get a palindrome (422442040244224).
The spelling of 120221020122203 in words is "one hundred twenty trillion, two hundred twenty-one billion, twenty million, one hundred twenty-two thousand, two hundred three".
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