Base | Representation |
---|---|
bin | 110111111110110111… |
… | …1001110111000000111 |
3 | 102111022102021101210022 |
4 | 1233331233032320013 |
5 | 3432203102244333 |
6 | 131121232045355 |
7 | 11454122531642 |
oct | 1577557167007 |
9 | 374272241708 |
10 | 120221134343 |
11 | 46a92772682 |
12 | 1b37199385b |
13 | b44bc611ab |
14 | 5b6686aa59 |
15 | 31d95d6c98 |
hex | 1bfdbcee07 |
120221134343 has 4 divisors (see below), whose sum is σ = 125448140208. Its totient is φ = 114994128480.
The previous prime is 120221134331. The next prime is 120221134381. The reversal of 120221134343 is 343431122021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120221134343 - 226 = 120154025479 is a prime.
It is a super-2 number, since 2×1202211343432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120221133343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2613502898 + ... + 2613502943.
It is an arithmetic number, because the mean of its divisors is an integer number (31362035052).
Almost surely, 2120221134343 is an apocalyptic number.
120221134343 is a deficient number, since it is larger than the sum of its proper divisors (5227005865).
120221134343 is an equidigital number, since it uses as much as digits as its factorization.
120221134343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5227005864.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 120221134343 its reverse (343431122021), we get a palindrome (463652256364).
The spelling of 120221134343 in words is "one hundred twenty billion, two hundred twenty-one million, one hundred thirty-four thousand, three hundred forty-three".
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