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12022130213 = 48724686099
BaseRepresentation
bin10110011001001001…
…10010011000100101
31011000211202111021222
423030210302120211
5144110131131323
65304535550125
7603630264212
oct131444623045
934024674258
1012022130213
11510a1a7405
1223b622b345
131197912722
1482093cb09
154a56929c8
hex2cc932625

12022130213 has 4 divisors (see below), whose sum is σ = 12046816800. Its totient is φ = 11997443628.

The previous prime is 12022130207. The next prime is 12022130273. The reversal of 12022130213 is 31203122021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12022130213 - 26 = 12022130149 is a prime.

It is a super-2 number, since 2×120221302132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12022130191 and 12022130200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12022130203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12342563 + ... + 12343536.

It is an arithmetic number, because the mean of its divisors is an integer number (3011704200).

Almost surely, 212022130213 is an apocalyptic number.

It is an amenable number.

12022130213 is a deficient number, since it is larger than the sum of its proper divisors (24686587).

12022130213 is an equidigital number, since it uses as much as digits as its factorization.

12022130213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24686586.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12022130213 its reverse (31203122021), we get a palindrome (43225252234).

The spelling of 12022130213 in words is "twelve billion, twenty-two million, one hundred thirty thousand, two hundred thirteen".

Divisors: 1 487 24686099 12022130213