Base | Representation |
---|---|
bin | 1010111011110010100111… |
… | …0000011000110111011001 |
3 | 1120120022200201211100220211 |
4 | 2232330221300120313121 |
5 | 3033433144341341441 |
6 | 41322550320451121 |
7 | 2350404102000310 |
oct | 256745160306731 |
9 | 46508621740824 |
10 | 12022314012121 |
11 | 39156a8925436 |
12 | 1422008779aa1 |
13 | 69291260745a |
14 | 2d7c5133d277 |
15 | 15cadbdc9a81 |
hex | aef29c18dd9 |
12022314012121 has 32 divisors (see below), whose sum is σ = 14854436536320. Its totient is φ = 9498238200000.
The previous prime is 12022314012073. The next prime is 12022314012127. The reversal of 12022314012121 is 12121041322021.
It is a cyclic number.
It is not a de Polignac number, because 12022314012121 - 221 = 12022311914969 is a prime.
It is a super-2 number, since 2×120223140121212 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12022314012092 and 12022314012101.
It is not an unprimeable number, because it can be changed into a prime (12022314012127) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 200505696 + ... + 200565646.
It is an arithmetic number, because the mean of its divisors is an integer number (464201141760).
Almost surely, 212022314012121 is an apocalyptic number.
It is an amenable number.
12022314012121 is a deficient number, since it is larger than the sum of its proper divisors (2832122524199).
12022314012121 is a wasteful number, since it uses less digits than its factorization.
12022314012121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100765.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12022314012121 its reverse (12121041322021), we get a palindrome (24143355334142).
The spelling of 12022314012121 in words is "twelve trillion, twenty-two billion, three hundred fourteen million, twelve thousand, one hundred twenty-one".
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