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1202313001034 = 2601156500517
BaseRepresentation
bin10001011111101111011…
…100000111100001001010
311020221101021000201220102
4101133233130013201022
5124144314112013114
62320200204125402
7152602302613205
oct21375734074112
94227337021812
101202313001034
11423997387aa2
12175024236862
13894ba862682
14422997bc93c
152141ccc92de
hex117ef70784a

1202313001034 has 4 divisors (see below), whose sum is σ = 1803469501554. Its totient is φ = 601156500516.

The previous prime is 1202313001031. The next prime is 1202313001073. The reversal of 1202313001034 is 4301003132021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 716926291225 + 485386709809 = 846715^2 + 696697^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1202313000997 and 1202313001015.

It is not an unprimeable number, because it can be changed into a prime (1202313001031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300578250257 + ... + 300578250260.

Almost surely, 21202313001034 is an apocalyptic number.

1202313001034 is a deficient number, since it is larger than the sum of its proper divisors (601156500520).

1202313001034 is an equidigital number, since it uses as much as digits as its factorization.

1202313001034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601156500519.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1202313001034 its reverse (4301003132021), we get a palindrome (5503316133055).

The spelling of 1202313001034 in words is "one trillion, two hundred two billion, three hundred thirteen million, one thousand, thirty-four".

Divisors: 1 2 601156500517 1202313001034