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12023204012114 = 253331127245829
BaseRepresentation
bin1010111011110101111011…
…0011011110000001010010
31120120101222202112001101112
42232331132303132001102
53033442010211341424
641323214512333322
72350435126606421
oct256753663360122
946511882461345
1012023204012114
113916015247619
121422216844242
13692a24b0c279
142d7cd76152b8
1515cb400cd60e
hexaef5ecde052

12023204012114 has 8 divisors (see below), whose sum is σ = 18038187771660. Its totient is φ = 6010474754896.

The previous prime is 12023204012089. The next prime is 12023204012129. The reversal of 12023204012114 is 41121040232021.

It can be written as a sum of positive squares in 2 ways, for example, as 11973904470889 + 49299541225 = 3460333^2 + 222035^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12023204012114.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 563612249 + ... + 563633580.

Almost surely, 212023204012114 is an apocalyptic number.

12023204012114 is a deficient number, since it is larger than the sum of its proper divisors (6014983759546).

12023204012114 is a wasteful number, since it uses less digits than its factorization.

12023204012114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1127251164.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 12023204012114 its reverse (41121040232021), we get a palindrome (53144244244135).

The spelling of 12023204012114 in words is "twelve trillion, twenty-three billion, two hundred four million, twelve thousand, one hundred fourteen".

Divisors: 1 2 5333 10666 1127245829 2254491658 6011602006057 12023204012114