Base | Representation |
---|---|
bin | 1010111011111010001010… |
… | …1001101100101011111001 |
3 | 1120120111221002102010210012 |
4 | 2232332202221230223321 |
5 | 3034001323112121213 |
6 | 41323523454031305 |
7 | 2350505261114240 |
oct | 256764251545371 |
9 | 46514832363705 |
10 | 12024342301433 |
11 | 39165498341a0 |
12 | 1422493aa8535 |
13 | 692b768a7c47 |
14 | 2d7da487d957 |
15 | 15cba9ec94a8 |
hex | aefa2a6caf9 |
12024342301433 has 16 divisors (see below), whose sum is σ = 15202534118400. Its totient is φ = 9237650931600.
The previous prime is 12024342301343. The next prime is 12024342301457. The reversal of 12024342301433 is 33410324342021.
It is not a de Polignac number, because 12024342301433 - 28 = 12024342301177 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12024342301433.
It is not an unprimeable number, because it can be changed into a prime (12024342301483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1099714883 + ... + 1099725816.
It is an arithmetic number, because the mean of its divisors is an integer number (950158382400).
Almost surely, 212024342301433 is an apocalyptic number.
It is an amenable number.
12024342301433 is a deficient number, since it is larger than the sum of its proper divisors (3178191816967).
12024342301433 is a wasteful number, since it uses less digits than its factorization.
12024342301433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2199440788.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 12024342301433 its reverse (33410324342021), we get a palindrome (45434666643454).
The spelling of 12024342301433 in words is "twelve trillion, twenty-four billion, three hundred forty-two million, three hundred one thousand, four hundred thirty-three".
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